First up, let's get the width of the area melted. Using the average height of a man (

which globally is 171cm, or 1.71m) for Karre until we find something else.

374 pixels = 1.71m

1 pixel = 1.71m/374 = 0.00457219251m

0.00457219251m X 51 = 0.233181818m

96 pixels = 0.233181818m

1 pixel = 0.233181818m/96 = 0.00242897727m

0.00242897727m X 104 = 0.252613636m

Next, let's find the dimensions of the Gemini-Star Destroyer. An X-wing is

11.76m across.

303 pixels = 11.76m

1 pixel = 11.76m/303 = 0.0388118812m

0.0388118812m X 1322 = 51.3093069m

29 pixels = 51.3093069m

1 pixel = 51.3093069m/29 = 1.76928644m

1.76928644m X 78 = 138.004342m

1.76928644m X 44 =77.8486034 meters

1.76928644m X 241 = 426.398032m

1.76928644m X 801 = 1417.19844m

1.76928644m X 786 = 1390.65914m

1.76928644m X 765 = 1353.50413m

1.76928644m X 790 = 1397.73629m

With that in our hands, let's now find the volume of the section melted. We can see the exact point at which Am managed to block it...

...so we'll scale up to there.

27 pixels = 138.004342m

1 pixel = 138.004342m/27 = 5.11127193m

5.11127193m X 979 = 5003.93522m (5.00393522km)

5.11127193m X 4 = 20.4450877m

5.11127193m X 707 = 3613.66925m

5.11127193m X 41 = 209.562149m

5.11127193m X 39 = 199.339605m

5.11127193m X 33 = 168.671974m

5.11127193m X 13 = 66.4465351m

5.11127193m X 128 = 654.242807m

5.11127193m X 410 = 2095.62149m

5.11127193m X 34 = 173.783246m

5.11127193m X 41 = 209.562149m

5.11127193m X 524 = 2678.30649m

5.11127193m X 19 = 97.1141667m

5.11127193m X 249 = 1272.70671m

2095.62149m - 1272.70671m - 209.562149m = 613.352631m

Firstly, we'll go for the total energy to melt the segment of the Star Destroyer cut. Volume of all the sections as rectangles (with a width and height of 0.252613636m and 20.4450877m respectively).

V = lhw

= 3613.66925 X 20.4450877 X 0.252613636

= 18663.5463m^3

V = lhw

= 66.4465351 X 20.4450877 X 0.252613636

= 343.176948m^3

V = lhw

= 654.242807 X 20.4450877 X 0.252613636

= 3378.97302m^3

V = lhw

= 613.352631 X 20.4450877 X 0.252613636

= 3167.7872m^3

We'll add the volumes together, then convert it to cm^3.

V = 18663.5463 + 343.176948 + 3378.97302 + 3167.7872

= 25553.4835m^3

= 25553483500cm^3

We'll go with a low end of aluminum (

2836.11219 joules/cm^3) and a high end of steel (

7309.87 joules/cm^3).

(Low end)

E = 2836.11219 X 25553483500

= 7.24725461e13 joules

= 17.321354230401528 kilotons

(High end)

E = 7309.87 X 25553483500

= 1.86792642e14 joules

= 44.6445129063097497 kilotons

With that all done, let's find the energy per second.

Timeframe is 10 seconds and 8 frames.

T = 1s/24

= 41.6666667ms X 8

= 0.333333334s + 10s

= 10.3333333s

(Low end)

E = 7.24725461e13/10.3333333

= 7.01347223e12 joules

= 1.676260093212237 kilotons

(High end)

E = 1.86792642e14/10.3333333

= 1.80767073e13 joules

= 4.3204367351816444 kilotons

That's also the minimum energy for Am stopping Karre's attack. Karre wins out though when R-DUO kicks into hyperdrive, and splits the Star Destroyer in half proper. Let's find the kinetic energy of the split. We'll calculate the armour larger two parts of the armour as two triangular prisms (it's not exact, but given the shape of the Star Destroyer and not taking the bridge into account, it'd be a low end in anycase).

A = hb/2

= 5003.93522 X 1417.19844/2

= 3545784.59m^2

V = bh

= 3545784.59 X 20.4450877

= 72493876.9 X 2

= 144987754m^3

Keeping consistent with what we've been working with above, we'll have a low end of aluminium (2600kg/m^3) and a high end of steel (7850kg/m^3) for our mass (

both values here).

(Low end)

M = 144987754 X 2600kg

= 376968160400kg

(High end)

M = 144987754 X 7850kg

= 1138153868900kg

Now for the middle, we'll go with two triangular pyramids and a triangular prism.

A = hb/2

= 1353.50413 X 426.398032/2

= 288565.749m^2

V = 1/3hb

= 1/3 X 288565.749 X 5003.93522

= 481321438 X 2

= 962642876m^3

A = hb/2

= 5003.93522 X 1353.50413/2

= 3386423.49m^2

V = hb

= 3386423.49 + 97.1141667

= 3386520.6m^3

V = 962642876 + 3386520.6

= 966029397m^3

As per usual with vehicle and machine mass calcs, I will be using mass of the light ship mass of container vessel 2700TEU, that being

102.56kg/m^3 (this is likely a huge low end, but it's the best I've got).

M = 966029397 X 102

= 98534998494kg

Adding those to our above values...

(Low end)

M = 376968160400kg + 98534998494kg

= 475503158894kg

(High end)

M = 1138153868900kg + 98534998494kg

= 1236688867394kg

Our penultimate directive is to find the speed.

Timeframe is 2 seconds and 12 frames.

T = 41.6666667ms X 12

= 0.5s + 2s

= 2.5s

407 pixels = 1397.73629m

1 pixel = 1397.73629m/407 = 3.4342415m

3.4342415m X 122 = 418.977463m

T = 418.977463m/2.5s

= 167.590985m/s

At last we shall have our energy!

(Low end)

KE = (0.5)mv^2

= (0.5) X 475503158894 X 167.590985^2

= 6.67766638e15 joules

= 1.596000568833652045 megatons

(High end)

KE = (0.5)mv^2

= (0.5) X 1236688867394 X 167.590985^2

= 1.73672783e16 joules

= 4.1508791347992355369 megatons